Favorable health insurance offers
As a patient of Dr. med. Livia Burkhard you have the possibility to be insured with the indicated health insurances in the corresponding basic insurance products and to save premiums. Assumptions for the premium calculation
Concordia
HMO model (HMO)
5.1 / 6
Customer satisfaction
CHF 249.10
Monthly premium*
Concordia
HMO model (HMO)
5.1 / 6
Customer satisfaction
CHF 249.10
Monthly premium*
Concordia
HMO model (HMO)
5.1 / 6
Customer satisfaction
CHF 249.10
Monthly premium*
*Monthly premium was calculated on .
Am I with the right doctor?
NEW
Test now whether your doctor is a good fit for you. With just 5 questions, you'll get an initial evaluation of how well your current doctor fits you. After 6 more questions, you'll get the full evaluation. Plus, you'll get tips on how to improve your interactions with your doctor.
About Dr. med. Livia Burkhard
Personal information:
- Acceptance of new patients – please check
Female
Nationality: Switzerland
German, English
Fax: 081 756 59 18
Qualifications
When looking for a doctor, it is a good idea to check their qualifications. It is important that the doctor has a specialist medical title in the relevant field of treatment. Doctors that hold such a… Read more
Specialist medical title
General internal medicine
General internal medicineIssued:
Switzerland, 2016
State exam
Doctor
Issued:
Switzerland, 2010
Proficiency certificates
2015
Medical practice laboratory (KHM)
Further private training and diplomas
2017
Small- and medium-dosage X-rays (KHM)
Licence to practise
Quality certificates
Quality certificates help patients to get a better picture of standards within the healthcare system. The bodies that award them check that an organization meets the criteria for a high standard of… Read more
Coronary heart disease
01.01.2022 - 31.12.2024
Practice locations
Dr. med. Livia Burkhard works at 1 location:
Services
There are no services listed for Dr. med. Livia Burkhard.
Is any of the information on the profile of Dr. med. Livia Burkhard incorrect or incomplete?